Grid.Create(Document, Line) Method

GridCreate(Document, Line) Method

Creates a new grid line.

Namespace: Autodesk.Revit.DB
Assembly: RevitAPI (in RevitAPI.dll) Version: 25.0.0.0 (25.0.0.0)
Syntax
public static Grid Create(
	Document document,
	Line line
)
Public Shared Function Create ( 
	document As Document,
	line As Line
) As Grid
public:
static Grid^ Create(
	Document^ document, 
	Line^ line
)
static member Create : 
        document : Document * 
        line : Line -> Grid

Parameters

document  Document
The document in which the new instance is created.
line  Line
A line which represents the location of the grid line.

Return Value

Grid
The newly created grid line.
Exceptions
ExceptionCondition
ArgumentException document is not a project document. -or- The input line is not on horizontal plane.
ArgumentNullException A non-optional argument was null
Remarks
The line should be on a horizontal plane.
Example
Copy
// Create the geometry line which the grid locates
 XYZ start = new XYZ(0, 0, 0);
 XYZ end = new XYZ(30, 30, 0);
 Line geomLine = Line.CreateBound(start, end);

 // Create a grid using the geometry line
 Grid lineGrid = Grid.Create(document, geomLine);

 if (null == lineGrid)
 {
     throw new Exception("Create a new straight grid failed.");
 }

 // Modify the name of the created grid
 lineGrid.Name = "New Name1";
   ' Create the geometry line which the grid locates
   Dim start As New XYZ(0, 0, 0)
   Dim [end] As New XYZ(30, 30, 0)
   Dim geomLine As Line = Line.CreateBound(start, [end])

   ' Create a grid using the geometry line
Dim lineGrid As Grid = Grid.Create(document, geomLine)

   If lineGrid Is Nothing Then
       Throw New Exception("Create a new straight grid failed.")
   End If

   ' Modify the name of the created grid
   lineGrid.Name = "New Name1"

No code example is currently available or this language may not be supported.

No code example is currently available or this language may not be supported.

See Also

M:Autodesk.Revit.DB.Grid.Create(Autodesk.Revit.DB.Document,Autodesk.Revit.DB.Line)